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PhysicsNLMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

Two boys of masses10 kgand8 kgare moving along a vertical rope, the former climbing up with the acceleration of2 m s-2while the later coming down with a uniform velocity of2 m s-1. Then tension in the rope at the fixed support is  (Takeg = 10 m s-2)

Options:

Answer:
A
Solution:

Since,m2moves with constant velocity.

∴f2=m2g

f2=8 ×10=80 N

Since, blockm1moves with acceleration




a=2 m s-2in the upward direction.

∴f1-m1g=m1a

∴f1=m1g+m1a

=10 ×10+10×2

=120 N

For equilibrium of rope,




T=f1+f2

=120+80 N

=200 N

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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