Three equal weights of mass 2kg each are hanging by a string passing over a fixed pulley. The tension in the string (in N) connecting B and C is

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Layout: A hangs on one side of the pulley; B hangs on the other side with C hanging below B. Each mass is 2 kg. T₁ is the string tension above B and T₂ is the tension between B and C.

A: $T_{1} - 2 g = 2 a$

B + C (4 kg): $4 g - T_{1} = 4 a$

Adding: $2 g = 6 a \Rightarrow a = \frac{g}{3}$

For C: $2 g - T_{2} = 2 a \Rightarrow T_{2} = 2 (g - \frac{g}{3}) = \frac{4 g}{3}$

Answer: (A).

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