Two blocks are in contact on a frictionless table. One has mass $m$ and other 2 $m$ . A force $F$ is applied on 2 $m$ as shown in figure. Next the same force $F$ is applied from the right on $m$ . In the two cases respectively, the ratio of the force of contact between the two blocks will be

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When force F is applied on 2 m from left, contact force, F 1 = m m + 2 m F = F 3 When force F is applied on m from right, contact force F 2 = 2 m m + 2 m F = 2 F 3 ∴ F 1 : F 2 = 1 : 2

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