A block starts moving up an inclined plane of inclination 30 ° with an initial velocity of v 0 . It comes back to its initial position with velocity v 0 2 . The value of the coefficient of kinetic fri

Question

A block starts moving up an inclined plane of inclination 30 ° with an initial velocity of v 0 . It comes back to its initial position with velocity v 0 2 . The value of the coefficient of kinetic friction between the block and the inclined plane is close to 1 1000 , The nearest integer to I is :

TestHub · Accepted Answer

A to B a 1 = g sin 30 ° + μg cos 30 ° = g 2 + μg 3 2 ; g = 10 m s 2 v 0 2 - 2 a 1 s = 0 s = v 0 2 a 1 .....(i) B to A a 2 = g 2 - μ 3 2 g V 0 2 2 = 2 a 2 s s = V 0 2 4 a 2 .....(ii) From equation (i) and (ii) V 0 2 a 1 = V 0 2 4 a 2 ⇒ a 1 = 4 a 2 ⇒ 5 + 5 3 μ = 4 5 - 5 3 μ ⇒ 5 + 5 3 μ ⇒ 25 3 μ = 15 ⇒ μ = 3 5 = 0 . 346 = 346 1000 So, 1 1000 = 346 1000

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