The coefficient of static friction, μ s , between block A of mass 2 kg and the table as shown in the figure is 0 . 2 . The maximum mass value of block B so that the two blocks do not move is (The stri

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The coefficient of static friction, μ s , between block A of mass 2 kg and the table as shown in the figure is 0 . 2 . The maximum mass value of block B so that the two blocks do not move is (The string and the pulley are assumed to be smooth and massless g = 10 m s − 2 )

TestHub · Accepted Answer

Condition for not moving the block is Tension in the string should be equal to static frictional force, here tention will be equal to m_bg

$\begin{array}{l} m_{B} g = μ_{s} m_{A} g \\ \Rightarrow m_{B} = μ_{s} m_{A} \\ or, m_{B} = 0.2 \times 2 = 0.4 kg \end{array}$

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