Physics - NLM Question with Solution | TestHub

Spring constant$\propto \frac{1}{\mathrm{l}\mathrm{e}\mathrm{n}\mathrm{g}\mathrm{t}\mathrm{h}}$

$k\propto \frac{1}{l}$,
Spring constant for the length ratios are$k_1=6k$

$k_2=3k$

$k_3=2k$

In series connection of springs,

$\frac{1}{k^{\prime }}=\frac{1}{6k}+\frac{1}{3k}+\frac{1}{2k}$

$\frac{1}{k^{\prime }}=\frac{6}{6k}$

$k^{\prime }=k$.

In parallel connection of springs,

$k^{\text{'}\prime }=6k+3k+2k$

$k^{\prime \prime }=11k$

$\frac{k^{\prime }}{k^{\prime \prime }}=\frac{1}{11}$

i.e.,$k^{\prime } :k^{\prime \prime }=1 :11$