We attach a mass m to a pulley as shown. With what force F (in N) should we pull the end of the thread (Figure ) so that the 'm' will go up with the acceleration $a = 2 m / s^{2}$ ? Mass of the pulley and thread is to be neglected. Take $m = 3.5 kg$ .
$m^{'}, a = 2 m / s^{2}$
?
$m = 3.5 kg$ )

Question

We attach a mass m to a pulley as shown. With what force F (in N) should we pull the end of the thread (Figure ) so that the 'm' will go up with the acceleration $a = 2 m / s^{2}$ ? Mass of the pulley and thread is to be neglected. Take $m = 3.5 kg$ .

$m^{'}, a = 2 m / s^{2}$

?

$m = 3.5 kg$ )

TestHub · Accepted Answer

The movable pulley carrying the mass is pulled up by two thread segments: 2 F − m g = ma 2 F − 35 = 3.5 × 2 F = 21 N

Physics - NLM Question with Solution | TestHub

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