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Physics - NLM Question with Solution | TestHub

PhysicsNLMFBD & EquilibriumMedium2 minPYQ_2016

PhysicsMediumsingle choice

A body of mass $60 kg$ is suspended by means of three strings $P, Q$ and $R$ as shown in the figure is in equilibrium. The tension in the string $P$ is

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Solution:

$R cos 6 0^{\circ} = Q = 60 g^{60 g}$ $R = \frac{60 g}{cos 6 0 ^{\circ}} = 120 g P = R sin 6 0^{\circ} = 120 g \times \frac{3}{2} = 103.9 g N$

Stream:AIIMSSubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2016

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