Physics - NLM Question with Solution | TestHub

If fireman slides down with some acceleration then its apparent weight decreases. For critical condition rope can bear only $\frac{2}{3}$ of the fireman's weight. Let $a$ is the minimum acceleration then, Tension in the rope $=m(g-a)=$ Breaking strength $$\begin{array}{ll}\Rightarrow & m(g-a)=\frac{2}{3}mg\\ \Rightarrow & =g-\frac{2g}{3}=\frac{g}{3}\end{array}$$