Physics - NLM Question with Solution | TestHub

Consider the force acting on the block as shown below



Given,$F=75\mathrm{ }\mathrm{N}$

$m=5 \mathrm{kg}$

Acceleration of the block

$F-mg\sin {30}^o=ma$

$\Rightarrow a=\frac{F-mg\sin {30}^o}{m}$

$\Rightarrow a=\frac{75-5g\sin {30}^o}{5}$

$a=\frac{50}{5}=10\mathrm{ m }{\mathrm{s}}^{-2}$upwards the inclined plane