Three equal weights of 3 kg each are hanging on a string passing over a frictionless pulley as shown in figure. The tension in the string between masses II and III will be (Take g = 10 m / sec 2 )

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Three equal weights of 3 kg each are hanging on a string passing over a pulley as shown in figure. If a is the common acceleration. T − 3 g = 3 a (For mass I) 3 g + T 1 ​ − T = 3 a (For mass II) 3 g − T 1 ​ = 3 a (For mass III) Adding, above three equations ​ 3 g = 9 a , a = g /3 T 1 ​ = 3 g − 3 a = 3 g − g = 2 g = 20 N ​

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