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PhysicsNLMFBD & EquilibriumHard2 minPYQ_2008

PhysicsHardsingle choice

$P, Q$ and $R$ are three coplanar forces acting at a point and are in equilibium. Given : $P = 1.9318 kg$ wt $[sin θ_{1} = 0.9659]$ , the value of $R$ (in $kg$ wt) is

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Answer:

Solution:

Using Lami's theorem, we have $\frac{P}{sin θ _{1}} = \frac{R}{sin 15 0 ^{\circ}} \Rightarrow \frac{P}{sin θ _{1}} = \frac{R}{sin ( 18 0 ^{\circ} - 3 0 ^{\circ} )} \Rightarrow \frac{1.9318 kgwt}{0.9659} = \frac{R}{1/2} \Rightarrow R = \frac{1.9318}{0.9659} \times \frac{1}{2} kgwt = 1 kgwt .$

Stream:AIIMSSubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2008

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