A bag is gently dropped on a conveyor belt moving at a speed of 2 m s - 1 . The coefficient of friction between the conveyor belt and bag is 0 . 4 Initially, the bag slips on the belt before it stops

Question

A bag is gently dropped on a conveyor belt moving at a speed of 2 m s - 1 . The coefficient of friction between the conveyor belt and bag is 0 . 4 Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion is : [Take g = 10 m s - 2 ]

TestHub · Accepted Answer

When the bag is dropped on the conveyor belt, the acceleration of the bag will be $a = μ g = 4 m s^{- 2}$
The bag will stop moving on the conveyor when the velocity of the bag and the velocity of the conveyor becomes equal.
$u = 0, v = 2 m s^{- 1}$
Using the equation of motion for constant acceleration,
$v^{2} = u^{2} + 2 a s$
$\Rightarrow s = 0.5 m$

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