System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass $2 m$ and $m$ just after the string is cut will be

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System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2 m and m just after the string is cut will be

TestHub · Accepted Answer

Initially under equilibrium of mass ' m ' T = m g Now, the string is cut. Therefore, T = m g force is decreased on mass m upwards and downwards on mass 2 m . a m ​ = m m g ​ = g (downwards) and a 2 m ​ = 2 m m g ​ = 2 g ​ (upwards)

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