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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMMedium2 minQB

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Two masses of 10 kg and 20 kg respectively are tied together by a massless spring. A force of 200 N is applied on a 20 kg mass as shown in figure. At the instant shown, the acceleration of 10 kg mass is $12 m / s^{2}$ right, the acceleration of 20 kg mass is :-

Options:

Answer:

Solution:

The spring pulls the 10 kg block with force

$F_{s} = (10 kg) (12 m/ s^{2}) = 120 N$

Apply Newton’s second law to the 20 kg block.

$200 - 120 = (20) a$

$a = 4 m/ s^{2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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