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PhysicsModern PhysicsNuclear physicsMedium2 minQB

PhysicsMediumsingle choice

The mass of proton, neutron and helium nucleus are respectively $1.0073 u, 1.0087 u an d 4.0015 u$ . The binding energy of helium nucleus is:

Answer:

Solution:

Given here, $m_{He} = 4.0015 u$ , $m_{p} = 1.0073 u$ and $m_{n} = 1.0087 u$ . Mass defect

$Δ m = 2 m_{p} + 2 m_{n} - m_{He} = 2 \times 1.0073 + 2 \times 1.0087 - 4.0015 = 0.0305 u$ Binding energy

$E = Δ m \times 931 M e V = 0.0305 \times 931 = 28.4 M e V$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: QB

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