If the electron in a hydrogen atom jumps from the third orbit to the second orbit, the emitted radiation has wavelength ( R = Rydberg Constant) :

Question

TestHub · Accepted Answer

The wavelength of the emitted radiation can be found using the Rydberg formula:

$\frac{1}{λ} = R (\frac{1}{n _{f}^{2}} - \frac{1}{n _{i}^{2}})$

where $n_{i}$ is the initial energy level (that is 3), $n_{f}$ is the final energy level ( that is 2), and $R$ is the Rydberg constant.

$\frac{1}{λ} = R (\frac{1}{2 ^{2}} - \frac{1}{3 ^{2}}) = R (\frac{1}{4} - \frac{1}{9}) = R (\frac{9 - 4}{36}) = \frac{5 R}{36}$

Therefore, $λ = \frac{36}{5 R}$ .

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