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PhysicsModern PhysicsX-raysMedium2 minQB

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When the voltage applied to an X-ray tube is increased 1.5 times, the short wave limit of the continuous X-ray spectrum shifts by 26 pm. Find the approx initial voltage applied to the tube.

Options:

Answer:

Solution:

$e V = \frac{h c}{λ}$ and $\frac{h c}{λ - Δ λ} = 1.5 e V$

$λ = 3Δ λ = 3 \times 26 = 78 pm = 0.78 \overset{˚}{A} V = \frac{12400}{0.78} \approx 16 kV .$

Subject:PhysicsTopic:Modern PhysicsSubtopic:X-rays

⏱ 2mℹ️ Source: QB

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