If the binding energy per nucleon in 3 7 Li and 2 4 He nuclei are 6.00 MeV and 7.00 MeV respectively, then in the reaction : p + 3 7 Li → 2 2 4 He , energy released in MeV is :

Question

If the binding energy per nucleon in 3 7 ​ Li and 2 4 ​ He nuclei are 6.00 MeV and 7.00 MeV respectively, then in the reaction : p + 3 7 ​ Li → 2 2 4 ​ He , energy released in MeV is :

TestHub · Accepted Answer

q = ( BE ) A ​ ( BE ) products ​ − ( BE ) reactant ​

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Doubts & Discussion

JEE Main (2026)