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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2021

PhysicsMediumsingle choice

If $λ_{1}$ and $λ_{2}$ are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of $λ_{1} : λ_{2}$ is :

Options:

Answer:

A

Solution:

$\frac{1}{λ_{1}} = R [\frac{1}{1^{2}} - \frac{1}{4^{2}}]$

$\frac{1}{λ_{2}} = R [\frac{1}{3^{2}} - \frac{1}{4^{2}}]$

$\frac{λ_{1}}{λ_{2}} = \frac{[\frac{1}{9} - \frac{1}{16}]}{[1 - \frac{1}{16}]} = \frac{7}{9 \times 15}$

$\frac{λ_{1}}{λ_{2}} = \frac{7}{135}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2021

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