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PhysicsModern PhysicsAtomic structureMedium2 minQB

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The angular momentum of an electron in the hydrogen atom is $h / π$ , where h is Planck's constant. The potential energy of this electron is

Answer:

Solution:

$L = h / π = 2 (h /2 π) \Rightarrow n = 2. PE = - \frac{27.2}{n ^{2}} = - \frac{27.2}{4} = - 6.8 eV$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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