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PhysicsModern PhysicsAtomic structureMedium2 minQB

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Let $ν_{1}$ be the frequency of the series limit of the Lyman series, $ν_{2}$ be the frequency of the first line of the Lyman series, and $ν_{3}$ be the frequency of the series limit of the Balmer series:

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Solution:

$ν_{1} = R c$ (Lyman limit); $ν_{2} = R c (1 - \frac{1}{4}) = \frac{3 R c}{4}$ (first Lyman line); $ν_{3} = \frac{R c}{4}$ (Balmer limit). Hence $ν_{1} - ν_{2} = \frac{R c}{4} = ν_{3}$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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