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PhysicsModern PhysicsAtomic structureMedium2 minQB

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A hydrogen atom and a $Li^{++}$ ion are both in the second excited state. If $L_{H}$ and $L_{L i}$ are their respective electronic angular momenta and $E_{H}$ and $E_{L i}$ their respective energies, then

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Solution:

Second excited state means $n = 3$ for both, so $L = 3 h /2 π$ for both. $∣ E ∣ = 13.6 Z^{2} / n^{2} : ∣ E_{H} ∣ =$ $13.6/9 < ∣ E_{L i} ∣ = 122.4/9$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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