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PhysicsModern PhysicsPhotoelectric effectMedium2 minQB

PhysicsMediumnumerical

Passage / Comprehension

When a surface is irradiated with light of wavelength $4950 \overset{˚}{A}$ , a photocurrent appears which vanishes if a retarding potential greater than 0.6 volts is applied across the phototube. When a second source of light is used, it is found that the retarding potential is changed to 1.1 volt. $(hc = 12375 eV - \overset{˚}{A})$

The work function (in eV) of the emitting surface is :

Answer:

1.90

Solution:

$\frac{h c}{λ _{1}} = \frac{12375}{4950} = 2.5 e V$

$ϕ = 2.5 - 0.6 = 1.9 e V$

Answer 1.90

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: QB

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