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PhysicsModern PhysicsAtomic structureMedium2 minQB

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The ratio of electrostatic potential energy of an orbiting electron to its kinetic energy in a H-atom is

Answer:

Solution:

$PE = - \frac{k Z e ^{2}}{r}$ and $K E = + \frac{k Z e ^{2}}{2 r}$ , so $PE : K E = - 2 : 1$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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