Physics - Modern Physics Question with Solution | TestHub

Energy of electron in nth orbit of hydrogen atom $\begin{array}{rl}& E_n=-\frac{13.6}{n^2}\mathrm{eV}\\ \Rightarrow & 3.4=-\frac{13.6}{n^2}\Rightarrow n^2=4\end{array}$ or, $\mathrm{n}=2$ Angular momentum of electron $\mathrm{L}=\frac{\mathrm{nh}}{2\pi }=\frac{2\mathrm{h}}{2\pi }=\frac{\mathrm{h}}{\pi }$