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PhysicsModern PhysicsPhotoelectric effectMedium2 minQB

PhysicsMediumsingle choice

For a photoelectric apparatus the variation of stopping potential $V_{s}$ versus wavelength of incident light $λ$ is:

Answer:

Solution:

$V_{s} = \frac{h c}{e λ} - \frac{ϕ}{e}$

The decreasing curve reaches zero at

$λ_{th} = \frac{h c}{ϕ}$

Graph 3 has this shape.

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: QB

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