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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsRadioactivityMedium2 minPYQ_2005

PhysicsMediumsingle choice

A radioactive material has a half-life of 10 days. What fraction of the material would remain after 30 days?

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Answer:

Solution:

$T_{1/2} = 10$ days, $T = 30$ days $T = n \times T_{1/2} . \Rightarrow n = \frac{T}{T _{1/2}} = \frac{30}{10} = 3 \frac{N}{N _{0}} = (\frac{1}{2})^{n} = (\frac{1}{2})^{3} = \frac{1}{8} = 0.125.$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2005

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