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PhysicsModern PhysicsNuclear physicsEasy2 minPYQ_2024

PhysicsEasynumerical

The radius of a nucleus of mass number $64$ is $4.8$ fermi. Then the mass number of another nucleus having radius of $4$ fermi is $\frac{1000}{x},$ where $x$ is _________.

Answer:

27.00

Solution:

Radius of a nucleus is given by, $R = R_{0} A^{1 / 3}$ .

Therefore, $R^{3} \propto A$

$\Rightarrow {(\frac{4.8}{4})}^{3} = \frac{64}{A}$

$\Rightarrow \frac{64}{A} = (1.2)^{3}$

$\Rightarrow \frac{64}{A} = 1.44 \times 1.2$

$\Rightarrow A = \frac{64}{1.44 \times 1.2} = \frac{1000}{x}$

$\Rightarrow x = \frac{144 \times 12}{64} = 27$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2024

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