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PhysicsModern PhysicsAtomic structureMedium2 minQB

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An electron revolving in $n^{th}$ Bohr orbit has magnetic moment $μ_{n}$ . If $μ_{n} \propto n^{x}$ , the value of $x$ is:

Answer:

Solution:

Magnetic moment of electron is given by, $μ_{n} = \frac{e hn}{4 π m _{e}}$ .
Clearly, $μ_{n} \propto n^{1}$ . Therefore, $x = 1$ .

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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