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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The ground state energy of $H$ -atom is $13.6 eV$ . The energy needed to ionize $H$ -atom from its second excited state is

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Answer:

Solution:

Ionization energy is the energy required to remove an electron from a gaseous atom or ion.

for this case, initially, the electron is in $3^{r d}$ orbit and we know for $H$ -atom $E_{n = 3} = - 1.51 e V$

Hence ionization energy of the electron is $1 .51 eV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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