Physics - Modern Physics Question with Solution | TestHub

The de-Broglie wavelength $\lambda$ of a moving particle is given by the relation:

$\lambda =\frac{h}{p}$

where $h$ is Planck's constant and $p$ is the momentum of the particle.

Since $h$ is a constant, we have:

$\lambda \propto \frac{1}{p}$

Thus, the de-Broglie wavelength is inversely proportional to the momentum of the particle.