Physics - Modern Physics Question with Solution | TestHub

Angular momentum of electron moving in $n^{\text{th }}$ orbit of hydrogen atom
Hence, $n=3$ Now, energy of electron in $3^{\text{rd }}$ orbit $\begin{array}{rl}E& =\frac{-13.6\times z^2}{n^2}\\ & =\frac{-13.6\times 1^2}{3^2}\\ & =-1.51\mathrm{eV}\\ & \approx -1.5\mathrm{eV}\end{array}$