When the electron orbiting in hydrogen atom in its ground state moves to the third excited state, the de-Broglie wavelength associated with it

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According to Bohr's model, the velocity of an electron in the $n$ -th orbit is given by $v \propto \frac{1}{n}$ .

The de-Broglie wavelength of the electron is $λ = \frac{h}{m v}$ .

Substituting the proportionality of velocity, we get $λ \propto n$ .

The ground state corresponds to $n = 1$ and the third excited state corresponds to $n = 4$ .

Since $n$ increases from $1$ to $4$ , the de-Broglie wavelength of the electron will increase.

Answer: will increase

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