Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Calculate the energy of the reaction
${Li}^{7} + p ⟶ 2_{2} {He}^{4}$
If the binding energy per nucleon in ${Li}^{7}$ and ${He}^{4}$ nuclei are $5.60 MeV$ and $7.06 MeV$ , respectively.

Options:

Answer:

Solution:

The binding energy of $Li = 39 .20 MeV$
The binding energy of ${He}^{4} = 28 .24 MeV$
The binding energy of $_{2} {He}^{4} = 56 .48 MeV$
$∴$ Energy $= 56 .48 - 39 .20 = 17 .28 MeV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...