Physics - Modern Physics Question with Solution | TestHub

From Einstein's photoelectric equation, $e{V}_0=hf-\Phi$, where $V_0$ is the stopping potential, $f$ is the frequency of incident radiation, and $\Phi$ is the work function of the material.

This relation shows that the magnitude of the stopping potential increases with an increase in the frequency of the incident radiation.

From the given graph, the magnitudes of the stopping potentials for curves $a,b,c$, and $d$ are in the order:

$|-V_0^1|<|-V_0^2|<|-V_0^3|<|-V_0^4|$

Thus, the stopping potentials follow the order $(V_0{)}_a<(V_0{)}_b<(V_0{)}_c<(V_0{)}_d$.

Consequently, the frequencies of the corresponding radiations must follow the same order:

$f_a<f_b<f_c<f_d$.

Answer: ${\mathrm{f}}_{\mathrm{a}}<{\mathrm{f}}_{\mathrm{b}}<{\mathrm{f}}_{\mathrm{c}}<{\mathrm{f}}_{\mathrm{d}}$