For a photosensitive material, work function is ' W 0 ' and stopping potential is ' V '. The wavelength of incident radiation is ( h = Planck's constant, c = velocity of lig

Question

For a photosensitive material, work function is ' W 0 ​ ' and stopping potential is ' V '. The wavelength of incident radiation is ( h = Planck's constant, c = velocity of light, e = electronic charge)

TestHub · Accepted Answer

According to Einstein's photoelectric equation, the energy of the incident radiation is the sum of the work function and the maximum kinetic energy of the emitted photoelectrons.

$E = W_{0} + K_{m a x}$

The maximum kinetic energy is related to the stopping potential $V$ by $K_{m a x} = e V$ .

The energy of the incident radiation in terms of wavelength $λ$ is $E = \frac{h c}{λ}$ .

Substituting these values into the photoelectric equation, we get:

$\frac{h c}{λ} = W_{0} + e V$

Rearranging the equation to solve for the wavelength $λ$ :

$λ = \frac{h c}{W _{0} + e V}$

Answer: $\frac{hc}{W _{0} + eV}$

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