The de-Broglie wavelength of an electron is the same as that of a photon. If velocity of electron is 25 % of the velocity of light, then the ratio of K.E. of electron and K.E. of photon will be:

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For photon, E P = h c λ p ⇒ λ p = h c E P For electron λ e = h m e v e = h v e 2 K e Given v e = 0 . 25 c . So, λ e = h × 0 . 25 c 2 K e = h c 8 K e Also λ p = λ e . Thus, h c E p = h c 8 K e ⇒ K e E p = 1 8

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