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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2019
PhysicsEasysingle choice

Taking the wavelength of first Balmer line in hydrogen spectrum(n=3 ton=2)as660 nm, the wavelength of the2ndBalmer line(n = 4 to n = 2)will be :

Options:

Answer:
B
Solution:

From Rydberg’s equation,
1λ=R1n2-1n22
1660×10-9=R122-132
1λ=R122-142
λ600×10-9=59×4×16×412
λ=488.9nm

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure
2mℹ️ Source: PYQ_2019

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