Physics - Modern Physics Question with Solution | TestHub

Nuclear radii $R=R_0{A}^{1/3}$ Where $R_0=1.2\mathrm{fm}$ or $R\propto (A{)}^{1/3}$ $\therefore \frac{R_{H_e}}{R_{G_e}}=\frac{(a{)}^{\frac{1}{3}}}{(A{)}^{\frac{1}{3}}}$ or $\frac{R_{H_e}}{2R_{B^{\epsilon }}}=\frac{(q{)}^{\frac{1}{3}}}{(\lambda {)}^{\frac{1}{3}}}$ Given $R_{Ge}=2R_{BC}$ $(A{)}^{1/3}=2\times (9{)}^{1/3}$ or $A=23\times 9=8\times 9=72$ $\therefore$ Number of nucleus is $\mathrm{Ge}$ is 72