Physics - Modern Physics Question with Solution | TestHub

The disintegration energy $Q$ for the nuclear fission of ${}^{235}\mathrm{U}\to {}^{140}\mathrm{Ce}+{}^{94}\mathrm{Zr}+n$ is ______ $\mathrm{MeV}$. Given atomic masses of ${}^{235}\mathrm{U}:235.0439u;{}^{140}\mathrm{Ce}:139.9054u$, ${}^{94}\mathrm{Zr}:93.9063u;n:1.0086u\text{, }$ Value of $c^2=931\mathrm{MeV}/\mathrm{u}$