The binding energy of deuteron ( 1 2 H ) is 1.15 MeV per nucleon and an alpha particle ( 2 4 He ) has a binding energy of 7.1 MeV per nucleon. Then in the reaction 1 2 H + 1 2 H ⟶ 2 2 He + Q

Question

The binding energy of deuteron ( 1 2 ​ H ) is 1.15 MeV per nucleon and an alpha particle ( 2 4 ​ He ) has a binding energy of 7.1 MeV per nucleon. Then in the reaction 1 2 ​ H + 1 2 ​ H ⟶ 2 2 ​ He + Q the energy released Q is:

TestHub · Accepted Answer

Given, 1 ​ H 2 + 1 ​ H 2 → 2 ​ He 4 + Q The total binding energy of the deutrons = 4 × 1.15 = 4.60 MeV The total binding energy of alpha particle = 4 × 7.1 = 28.4 MeV The energy released in the process = 28.4 − 4.60 = 23.8 MeV .

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