The wavelength of the K β -line for 92 U 235 is (Take R ∞ = 1.097 × 1 0 7 m − 1 )

λ 1 = R ( Z − 1 ) 2 ( 1 2 1 − 3 2 1 ) = 1.097 × 1 0 7 × 9 1 2 × 9 8 λ ≈ 0.12 A ˚ ≈ 0.15 A ˚ (nearest option).

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The wavelength of the $K_{β}$ -line for $_{92} U^{235}$ is (Take $R_{\infty} = 1.097 \times 1 0^{7} m^{- 1}$ )

Answer:

Solution:

$\frac{1}{λ} = R (Z - 1)^{2} (\frac{1}{1 ^{2}} - \frac{1}{3 ^{2}}) = 1.097 \times 1 0^{7} \times 9 1^{2} \times \frac{8}{9}$

$λ \approx 0.12 \overset{˚}{A} \approx 0.15 \overset{˚}{A} (nearest option).$

Subject:PhysicsTopic:Modern PhysicsSubtopic:X-rays

⏱ 2mℹ️ Source: QB

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