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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2022
PhysicsEasystatement

When light of frequency twice the threshold frequency is incident on the metal plate, the maximum velocity of emitted electron isv1. When the frequency of incident radiation is increased to five times the threshold value, the maximum velocity of emitted electron becomesv2. Ifv2=xv1, the value ofxwill be _____ .

Answer:
2
Solution:

Maximum kinetic energy is expressed as Kmax=hf-ϕ, here, ϕ is work function of metal.

For first case, 12mv12=h2f0−f0

For second case, 12mv22=h5f0−f0

⇒v22v12=41⇒v2v1=2

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect
⏱ 2mℹ️ Source: PYQ_2022

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