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PhysicsModern PhysicsDe Broglie & Matter WavesHard2 minPYQ_2017

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The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature $T$ (Kelvin) and mass $m$ is:NEET 2017

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Answer:

Solution:

De-Broglie wavelength,
$λ = \frac{h}{m v}$ $= \frac{h}{\sqrt{2 m (K E)}}$ $= \frac{h}{\sqrt{2 m (\frac{3}{2} k T)}}$
(Since K.E. of a thermal neutron $= \frac{3}{2} k T$ )
$\Rightarrow$ $λ = \frac{h}{\sqrt{3 m k T}}$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2017

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