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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2022
PhysicsEasystatement

Anαparticle and a carbon12atom has same kinetic energyK. The ratio of their de-Broglie wavelengthsλα:λC12is

Options:

Answer:
A
Solution:

De-Broglie wavelength is stated as λ=hp=h2mK, where, K is kinetic energy and m is mass.

Here, Kα=KC12.

Now, the ratio λαλC12=12m4m=3:1

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves
2mℹ️ Source: PYQ_2022

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