Physics - Modern Physics Question with Solution | TestHub

Momentum of striking electrons, $p=\frac{h}{\lambda }$ $\therefore$ Kinetic energy of striking electrons, $K=\frac{p^2}{2m}=\frac{h^2}{2m{\lambda }^2}$ This is also, maximum energy of $X$-ray photons. Therefore, $\frac{hc}{{\lambda }_0}=\frac{h^2}{2m{\lambda }^2}$ or ${\lambda }_0=\frac{2m{\lambda }^{2}c}{h}$ $\therefore$ Correct option is (a).