A hydrogen atom in its ground state absorbs 10 . 2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of (Given, Planck's constant = 6 . 6 × 10 - 34 Js

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A hydrogen atom in its ground state absorbs 10 . 2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of (Given, Planck's constant = 6 . 6 × 10 - 34 Js ).

TestHub · Accepted Answer

Energy absorbed is given by, Δ E = 13 . 6 × 1 n 1 2 - 1 n 2 2 10 . 2 = 13 . 6 × 1 n 1 2 - 1 n 2 2 Therefore, we get, n 1 = 1 & n 2 = 2 The change in angular momentum Δ L = n 2 h 2 π - n 1 h 2 π = h 2 π = 1 . 05 × 10 - 34 J s

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