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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2021
PhysicsMediumstatement

The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of100 V. What should nearly be the ratio of their wavelengths? mp=1.00727 u,me=0.00055 u

Options:

Answer:
D
Solution:

λ=hmv=h2mK=h2mqV

λ1λ2=m2 m1

λeλp=mpme=1831.4=42.79

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves
2mℹ️ Source: PYQ_2021

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