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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2021

PhysicsEasysingle choice

Ratio of centripetal acceleration for an electron revolving in $3^{rd}$ and $5^{th}$ Bohr orbit of hydrogen atom is

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Solution:

Centripetal acceleration $a = \frac{v ^{2}}{r}$ For hydrogen atoms, $v \propto \frac{1}{n}$ and $r \propto n^{2}$ $∴ a \propto \frac{1}{n ^{4}} ∴ \frac{a _{3}}{a _{5}} = (\frac{5}{3})^{4} = \frac{625}{81}$

Stream:MHT_CETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2021

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